Search results
Jul 20, 2016 · Regarding your first question.The pipe works as follows: numberValue | number: {minIntegerDigits}.{minFractionDigits}-{maxFractionDigits} minIntegerDigits: Minimum number of integer digits to show before decimal point,set to 1by default. minFractionDigits: Minimum number of integer digits to show after the decimal point.
Feb 16, 2013 · 3. The & operator in Java is the bitwise-and operator. Basically, (number & 1) performs a bitwise-and between number and 1. The result is either 0 or 1, depending on whether it's even or odd. Then the result is compared with 0 to determine if it's even. Here's a page describing bitwise operations.
Jun 29, 2015 · 87. I have a simple select statement. I want to add a temporary column that will represent number the of rows in my result set. I tried this -. declare @num int set @num = 0; select t.A, t.B, t.C, (@count + 1) as number from tableZ as t. It assigns the 1 to all rows. I tried @count = @count + 1 and it did not work.
Feb 11, 2011 · Task: generate random number between 1 and 6. Math.random() returns floating point number between 0 and 1 (like 0.344717274374 or 0.99341293123 for example), which we will use as a percentage, so Math.floor(Math.random() * 6) + 1 returns some percentage of 6 (max: 5, min: 0) and adds 1.
Jan 15, 2012 · I've got a solution that counts the bits in O (Number of 1's) time: bitcount (n): count = 0 while n > 0: count = count + 1 n = n & (n-1) return count. In worst case (when the number is 2^n - 1, all 1's in binary) it will check every bit. Edit: Just found a very nice constant-time, constant memory algorithm for bitcount.
Dec 15, 2009 · While list(map(int, str(x))) is the Pythonic approach, you can formulate logic to derive digits without any type conversion: from math import log10. def digitize(x): n = int(log10(x)) for i in range(n, -1, -1): factor = 10**i. k = x // factor. yield k. x -= k * factor.
Oct 26, 2013 · [^\d]{1,} - matches if no number (between [0-9]) is found [\s] - matches if a white space, tab or line break is found. With this approach there's no limit or restriction in terms of symbols allowed. If you want to limit to few symbols allowable, just change [^\W] with [^YourSymbols].
Jul 28, 2009 · Step 4. Get your random number into the range you want. The general formula for doing so is this: int random_number = rand() % range + min; Where range is how many (consecutive) numbers you want to choose from, and min is the smallest of these. So to generate a number between 1 and 100, range is 100 and min is 1:
Aug 16, 2013 · I got here because I wanted to create a range between -10 and 10 in increments of 0.1 using list comprehension.
To generate a random number "in between two numbers", use the following code: Random r = new Random(); int lowerBound = 1; int upperBound = 11; int result = r.nextInt(upperBound-lowerBound) + lowerBound; This gives you a random number in between 1 (inclusive) and 11 (exclusive), so initialize the upperBound value by adding 1.
