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Dec 16, 2015 · Help. No, it's an arithmetic sequence with initial term 3 and common difference 3. A geometric sequence has a common ratio between terms. An arithmetic sequence has a common difference between terms. If a sequence of Real numbers is both a geometric sequence and an arithmetic sequence then it is constant. Note I say Real numbers.
The pattern to this sequence is that every 10 terms, the sequential differences doubles. This sequence is a modified version of the sequence I asked about in this post: What's the mathematical
May 24, 2018 · a_1 = 3 a_n = a_{n-1}+3 A recursive formula is a formula that describes a sequence a_0, a_1, a_2, ... by giving a rule to compute a_i in terms of its predecessor(s), instead of giving an immediate representation for the i-th term. In this sequence, we can see that each term is three more than its predecessor, so the formula would be a_1 = 3 a_n = a_{n-1}+3 Note that every recursive formula ...
How many terms of the progression $3,6,9,12,\dots$ must be taken to have a sum not less than $2000$?
" Set {3, 6, 9, 12 , 15...} is a subset of N since its an injection of N. the set is countable and a subset of a countable set is also countable. thus the set {3 , 6 , 9 , 12 , 15 ... } is countable as well since its a subset of N." does it look right? $\endgroup$ –
For example, 3, 6 3, 6 and 15 15 are a few of the common terms in these two sequences, but I need to know the exact number of common terms. My approach: nth n t h term of S1 = [n(n + 1)] 2 S 1 = [n (n + 1)] 2. kth k t h term of S2 = 3k S 2 = 3 k. Now for common terms:
Feb 18, 2015 · and Find a minimum SOP expression for: f(w,x,y,z) = ∑ m (1,3,5,9,11,14)+d(4,6,7,12) Show all the "prime implicants" and "essential prime implicants" This is what I came up with: But as you can see, I don't have any essential prime implicants whatsoever. So I'm worried that I'm doing something horribly wrong.
May 30, 2018 · 48 Look at the sequence of differences: 3, 6, 12, 21, 33 The differences are 3, 6, 9, 12 so the next difference is 15. 33 + 15 = 48
Computing powers of 3 (mod 21) you get ${3, 9, 6, 18, 12, 15}$ and then back to 3 again. That makes the set of numbers a cyclic group of order 6 generated by 3 with $3^6 = 15$ the identity. Share
For the set X = { 2,3,6,12,24,36}, a relation ≤ is defined as x ≤ y if x divides y. Draw the Hasse diagram for (X,≤) . Answer the following: (i) What are the maximal and minimal elements? (ii) Give one example of chain & antichain. (iii) Is the poset a lattice? I have tried to solve this question as follows:
