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  1. Dictionary
    con·vo·lu·tion
    /ˌkänvəˈlo͞oSH(ə)n/

    noun

    More definitions, origin and scrabble points

  2. Oct 26, 2010 · 27. I am currently learning about the concept of convolution between two functions in my university course. The course notes are vague about what convolution is, so I was wondering if anyone could give me a good explanation. I can't seem to grasp other than the fact that it is just a particular integral of two functions.

  3. Intuition for Convolution. A convolution is the amount of an overlap area of one function f as it is shifted over another function g at a given time offset. Example using discrete valued functions. Let’s say we are transforming a certain function f(t) by passing it through a filter g(t) to get the output h(t): f(t) -> [ g(t) ] -> h(t)

  4. Sep 6, 2015 · The definition of convolution is known as the integral of the product of two functions. (f ∗ g)(t)∫∞ −∞ f(t − τ)g(τ)dτ (f ∗ g) (t) ∫ − ∞ ∞ f (t − τ) g (τ) d τ. But what does the product of the functions give? Why are is it being integrated on negative infinity to infinity?

  5. Jul 4, 2015 · 2. Let f, g ∈ L1(R), we may define the convolution of f and g as follows: f ∗ g(x) = ∫Rf(x − y)g(y)dy, (x ∈ R). It is well known that it can be defined on general locally compact group as well. It the operation convolution (I think) in analysis (perhaps, in other branch of mathematics as well) is like one of the most useful operation ...

  6. As a special case, the convolution of a function f(t) f (t) with the Dirac delta function gives f(0) f (0) (the response of the system at t = 0 t = 0). Because of the above, the input signal is thought of as "smearing" the impulse response on the time axis. Mathematically, it means that convolution of a given function f f with a smooth function ...

  7. asked Mar 16, 2014 at 18:05. Elle Najt. 21k 6 39 84. 1. A shift-invariant linear operator T is completely determined by its impulse response T(δ) = f (where δ is the Dirac delta function). You can show that for any function g, T(g) = f ∗ g. This motivates the definition of convolution. – littleO. Mar 16, 2014 at 19:19.

  8. Jan 31, 2018 · 3. We will define the convolution (slightly unconventionally to match Rudin's proof) of f and g as follows: (f ⋆ g)(x) = ∫1 − 1f(x + t)g(t)dt (0 ≤ x ≤ 1) Let f(x) f (x) Find a piecewise algebraic expression for f ⋆ δ10 f ⋆ δ 10. Repeat the exercise for f ⋆ δ20 f ⋆ δ 20. In what sense does f ⋆ δn f ⋆ δ n.

  9. Intuition for Convolution. A convolution is an amount of overlap of one function f as it is shifted over another function g at a given time offset. Let’s say we are transforming a certain function f (t) by passing it through a filter g (t) to get the output h (t): f(t) -> [ g(t) ] -> h(t)

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  11. Mar 14, 2015 · $\begingroup$ I doubt you can define convolution without some group structure on the manifold. $\endgroup$ – Olivier Bégassat Commented Mar 14, 2015 at 17:19

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