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  1. www.mathway.com › popular-problems › AlgebraGraph f(x)=-2x^2 | Mathway

    Algebra. Graph f (x)=-2x^2. f (x) = −2x2 f ( x) = - 2 x 2. Find the properties of the given parabola. Tap for more steps... Direction: Opens Down. Vertex: (0,0) ( 0, 0) Focus: (0,−1 8) ( 0, - 1 8) Axis of Symmetry: x = 0 x = 0. Directrix: y = 1 8 y = 1 8. Select a few x x values, and plug them into the equation to find the corresponding y y values.

  2. www.mathway.com › popular-problems › AlgebraGraph f(x)=2x-2 | Mathway

    Algebra. Graph f (x)=2x-2. f (x) = 2x − 2 f ( x) = 2 x - 2. Rewrite the function as an equation. y = 2x− 2 y = 2 x - 2. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 2 2. y-intercept: (0,−2) ( 0, - 2) Any line can be graphed using two points.

  3. x^2: x^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: x^{\circ} \pi \left(\square\right)^{'} \frac{d}{dx} \frac{\partial}{\partial x} \int \int_{\msquare}^{\msquare} \lim \sum \infty \theta (f\:\circ\:g) f(x)

  4. Jun 10, 2016 · Explanation: When we have a question that gives a function, such as f (x) = 2x2 and we are then asked what that function would then be with f (2x), we substitute the 2x in for every x we see. Like this: f (2x) = 2(2x)2. We can now simplify it: f (2x) = 2(4x2) f (2x) = 8x2. Answer link.

  5. x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120) \lim _{x\to 0}(x\ln (x)) \int e^x\cos (x)dx \int_{0}^{\pi}\sin(x)dx \sum_{n=0}^{\infty}\frac{3}{2^n} Show More

  6. Evaluating Functions. To evaluate a function is to: Replace ( substitute) any variable with its given number or expression. Like in this example: Example: evaluate the function f (x) = 2x+4 for x=5. Just replace the variable "x" with "5": f ( 5) = 2× 5 + 4 = 14. Answer: f (5) = 14.

  7. Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0. x=\frac{-\left(-3\right)±\sqrt{\left(-3\right)^{2}-4\times 2\left(-2\right)}}{2\times 2}

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    f(x)=2x2 answer
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