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  1. Feb 26, 2011 · I want to get the list of dates in between these two dates. Can anyone help me pointing the mistake in my query. select Date,TotalAllowance from Calculation where EmployeeId=1 and Date between 2011/02/25 and 2011/02/27 Here Date is a datetime variable.

  2. Dec 21, 2017 · I have two different dates and I want to know the difference in days between them. The format of the date is YYYY-MM-DD. I have a function that can ADD or SUBTRACT a given number to a date: def

  3. Jun 3, 2019 · Note that the dateutil.parser.parse() method can handle a wider variety of date formats than datetime.datetime.strptime(), so you may not need to specify a format string for the dates in your file. However, if you know the exact format of the dates in your file, you can still use strptime() to parse them if you prefer.

  4. Jan 29, 2009 · The easiest way to compare dates in javascript is to first convert it to a Date object and then compare these date-objects. Below you find an object with three functions: dates.compare(a,b) Returns a number:-1 if a < b; 0 if a = b; 1 if a > b; NaN if a or b is an illegal date; dates.inRange (d,start,end) Returns a boolean or NaN:

  5. Jan 4, 2012 · The date_diff() function returns the difference between two DateTime objects. If the first date is before the second date a positive number of days will be returned; otherwise a negative number of days:

  6. May 22, 2014 · You can use the date_parser argument to read_csv. In [62]: from pandas.compat import StringIO In [63]: s = """date,value 30MAR1990,140000 30JUN1990,30000 30SEP1990,120000 30DEC1990,34555 """ In [64]: from pandas.compat import StringIO In [65]: import datetime

  7. Apr 12, 2013 · For my queries on MS Access, I can compare dates with this syntax: SELECT COUNT(orderNumber) AS Total FROM Orders WHERE orderDate >=#2003/04/01# AND orderDate <=#2003/06/30#; Where the output is the number of orders between 2003-04-01 and 2003-06-30.

  8. However, if the dates are datetime.datetime objects, it is not as straightforward because .days rounds down no matter if the difference is positive or negative. For example, in the following example, the time difference between the two datetimes is 5 hours and if we use timedelta.days to get the number of days, that difference becomes 0 days or -1 day depending on which datetime was subtracted ...

  9. Jan 20, 2009 · you can do the same for START and END filter parameters as well. Always make the start date a datetime and use zero time on the day you want, and make the condition ">=". Always make the end date the zero time on the day after you want and use "<". Doing that, you will always include any dates properly, regardless of the time portion of the date.

  10. Feb 9, 2011 · If you have GNU date, it allows to print the representation of an arbitrary date (-d option). In this case convert the dates to seconds since EPOCH, subtract and divide by 24*3600.

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