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Step-by-step explanation: General Rule for arithmetic sequence: an = a₁ + (n-1) (d) Given: 3, 6, 9, 12, ... First term, a₁ = 3. Common difference, d = (a₂-a₁) d = (6 - 3); d = 3. Substitute above given values for a₁ and d: an = 3 + (n-1) ( 3) an = 3 -3 + 3n. an = 3n. Advertisement. Answer. 7 people found it helpful. lelita17. report flag outlined.
A sequence 3,6,9,12... To find, The nth term of the sequence. Solution, The first term of the given sequence is 3 and the second term is 6. Let us first calculate the common difference between the term. If a1, a2 ,a3, a4 are in sequence the common difference is calculated by a2-a1, a3-a2, a4-a3.
Solution. The correct option is A 3n, 21. In the given sequence of numbers, 1st number = 3×1 = 3. 2nd number = 3×2 = 6. 3rd number = 3×3 = 9. 4th number = 3×4 = 12. . . nth number = 3×n. = 3n. ∴ The expression for the sequence is 3n. now, the 7th term = 3×7 = 21. Hence, the 7th term is 21. Suggest Corrections. 1. Similar questions.
What is LCM of 3, 6, 9 and 12. The Least Common Multiple or Lowest Common Multiple of 3, 6, 9 and 12 is 36. How to Find LCM of 3, 6, 9 and 12? LCM of 3, 6, 9 and 12 can be determined using three methods: Prime Factorisation; Division method; Listing the multiples; LCM of 3, 6, 9 and 12 Using Prime Factorisation Method
3 + 6 + 9 + 12 + 15 3 + 6 + 9 + 12 + 15. This is the formula to find the sum of the first n n terms of the sequence. To evaluate it, the values of the first and n n th terms must be found. Sn = n 2 ⋅(a1 +an) S n = n 2 ⋅ ( a 1 + a n) This is an arithmetic sequence since there is a common difference between each term.
Solution. Verified by Toppr. The given sequence is an A.P. with first term a =3 and common difference d = 3. Let there be n terms in the given sequence. Then, nth term =111. a+(n−1)d = 111. 3+(n−1)×3 = 111. n =37. Thus, the given sequence contains 37 terms. Was this answer helpful? 20. Similar Questions. Q 1.
Consider the sequence : 3, 6, 9, 12, ....., 99 a) How many terms are there in the given sequence? b) Find the mean of the sequence. c) Find the sum of squares of each terms of the given sequence. d) Find the variance of the sequence.
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Notice the difference between each term of the sequence is 3. From there, you can build up your reasoning. First term is 3. Second term is 3 + 3 = 6. Third term is 3 + 3 + 3 = 9. Fourth term is 3 + 3 + 3 + 3 = 12.
